In triangle ABC, angle C = 90g. AB = 15, AC = 9. Find the tangent of angle B.

<C = 90 °; AB = 15; AC = 9;

tg B = AC / CB;

CB² = AB² – AC²; CB² = 225 – 81 = 144;

CB = √144; CB = 12;

tg B = 9/12 = 3/4;



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