In triangle ABC, angle C is 45 °, AD is the bisector of the angle. A, the ADB angle is 70 ° night

In triangle ABC, angle C is 45 °, AD is the bisector of the angle. A, the ADB angle is 70 ° night, the degree measure of angle B.

The ADВ angle is the outer angle at the vertex D of the AСD triangle.

The outer corner of a triangle is equal to the sum of its two inner angles that are not adjacent to it.

Angle ADВ = (СAD + AСD).

СAD angle = (ADВ – AСD) = (70 – 45) = 25.

Since the BP is the bisector of the angle BAC, the angle ABC = 2 * СAD= 2 * 25 = 50.

The sum of the inner angles of the triangle is 180, then the angle ABC = (180 – BAC – BCA) = (180 – 50 – 45) = 85.

Answer: The angle ABC is 85.