In triangle ABC, angle C is 90∘, AC = 12, tgA = 2√10 ÷ 3. Find AB.

univerkov | November 29, 2020 | education

tg = opposite leg / adjacent leg => tg (2 * √ (10) / 3 = CB / AC => CB = AC * 2 * √ (10) / 3 => CB = 12 * 2 * √ (10) / 3 => CB = 8 * √ (10)
Answer: CB = 8 * √ (10)

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