In triangle ABC, angle C is 90 °. ВС = 12, SinB = 3/5. Find AB.
| August 1, 2021 | education
Knowing the sine of the angle ABC, we determine the cosine of this angle.
Cos2ABC = 1 – Sin2ABC = 1 – (3/5) ^ 2 = 1 – 9/25 = 16/25.
CosABC = 4/5.
Through the cosine of the angle and the adjacent leg, we determine the length of the hypotenuse AB.
CosABS = BC / AB.
AB = BC / CosABC = 12 / (4/5) = 12 * 5/4 = 15 cm.
Answer: The length of the hypotenuse AB is 15 cm.
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