In triangle ABC, angle C is 90 ° AB = 15 TgA = 1. Find TgA * CtgB.

We know that tangent is the ratio of the opposite leg to the adjacent leg. Then TgA = CB / AB = 1
Knowing that AB = 15, we can calculate that AB = CB = 15
We know that the cotangent is the ratio of the adjacent leg to the opposite one, then CtgB = СB / AB = 15/15 = 1
Then TgA * CtgB = 1 * 1 = 1



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