In triangle ABC, angle C is 90 °, AB = 25, AC = 10√6. find cos A.

1) The cosine of the angle is the ratio of the adjacent leg to the hypotenuse;

2) In our problem for angle A, the adjacent leg will be AC, and the hypotenuse AB, by condition, AC = 10√6, AB = 25, then we get:

cos∠A = AC / AB = 10√6 / 25

Reduce the fraction by 5, we get:

cos∠A = 2√6 / 5.

Answer: 2√6 / 5.



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