In triangle ABC, angle C is 90 °, AB = 30 cm, AC = 3√19 cm. Find sin A.

First way.

By the Pythagorean theorem, we determine the length of the BC leg.

BC ^ 2 = AB ^ 2 – AC ^ 2 = 900 – 171 = 729.

BC = 27 cm.

Determine the sine of the angle BAC.

SinBAC = BC / AB = 27/30 = 9/10.

Second way.

Determine the cosine of the angle BAC.

CosBAC = AC / AB = 3 * √19 / 30 = √19 / 10.

Determine the sine of the angle BAC.

Sin2BAC + Cos2BAC = 1.

Sin2BAC = 1 – Cos2BAC = 1 – (19/100) = 81/100.

SinBAC = 9/10.

Answer: The sine of the ICA angle is 9/10.



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