In triangle ABC, angle C is 90 °, AC = √51, BC = 7, Find sin A.

Solution:
1) Because angle C = 90 °, then AC and BC – legs, hypotenuse – AB. Sinus is the ratio of the opposite leg to the hypotenuse:
sinA = BC / AB.
AB will be found by the Pythagorean theorem: AB² = AC² + BC² = (√51) ² + 7² = 100, AB = 10.
sinA = 7/10 = 0.7.



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