In triangle ABC, angle C is 90 AC 3√21 BC 6 find sinA

1) sin A = BC / AB (because the sine is equal to the ratio of the opposite leg to the hypotenuse)

2) By the Pythagorean theorem, we find AB:

AB ^ 2 = BC ^ 2 + AC ^ 2

Hence:

AB ^ 2 = 36 + 189 = 225

AB = 15

3) sin A = 6 \ 15 = 0.4



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