In triangle ABC, angle C is 90, AC = 8, tg a = 0.5. Find BC.

To find the tangent of an acute angle, you need to divide the opposite leg into the adjacent one. In our case, leg BC lies opposite corner A, and leg AC is next to it. Now we find leg BC through the tangent of angle A and the well-known leg AC:

tg ⦟A = BC / AC;

0.5 = BC / 8;

BC = 0.5 * 8 = 4 cm.

Answer: BC = 4 cm.