In triangle ABC, angle C is 90 and the bisectors of angles A and B meet at point E. Find triangle AEB

Since triangle ABC is rectangular, the sum of its acute angles is 90.

Angle (BAC + ABC) = 90.

Since the Segments AM and BK are the bisectors of the angles ABC and CBA, then the angle EBA = ABC / 2, the angle EAB = BAC / 2.

Angle (EBA + EAB) = ABC / 2 + CBA / 2 = (ABC + CBA) / 2 = 90/2 = 45.

Then in triangle ABE the angle AEB = (180 – 45) = 135.

Answer: The angle AEB is 135.