In triangle ABC, angle C is 90 BC 2√15 AB 8 find cosA

1) Cosine A – the ratio of the adjacent leg to the hypotenuse.

That is, cos A = AC / AB

2) From a right-angled triangle we find AC (by the Pythagorean theorem)

AC ^ 2 = AB ^ 2 – BC ^ 2

AC ^ 2 = 64 – 60 = 4

AC = 2

3) cos A = 2/8 = 0.25



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