In triangle ABC, angle C is 90 °, BC = 2, sinsA = 0.4. Find AB

Consider a triangle ABC, angle <C = 90 ° – a rectangular triangle with hypotenuse AB, AC and CB – legs, CB = 2 cm, sin A = 0.4.
By definition of the sine of an angle in a right-angled triangle, it is equal to the ratio of the opposite leg to the hypotenuse:
sin A = CB / AB
Let us express the hypotenuse СВ from this expression:
AB = СВ / sin A = 2 / 0.4 = 5 cm.
Answer: the length of the hypotenuse Av is 5 cm.



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