In triangle ABC, angle C is 90. BC = 9. Sin A = 0.75. Find AB
| September 20, 2021 | education
Given: right-angled triangle ABC;
angle C = 90;
sin A = 0.75;
BC = 9;
Find: AB -?
Solution:
1) Consider a right-angled triangle ABC. The sine of the angle in a right-angled triangle is equal to the ratio of the opposite leg to the hypotenuse. Hence:
sin A = CB / AB;
AB = BC / sin A;
AB = 9: 0.75;
AB = 900 * 75;
AB = 12.
Answer: AB = 12.
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