In triangle ABC, angle C is 90, CH is height, AB = 49, sin A = 5/7. Find BH.
| June 12, 2021 | education
In a right-angled triangle ABC, SinA = BC / AB.
BC = AB * SinA = 49 * 5/7 = 7 * 5 = 35 cm.
In a right-angled triangle BCH, the angle BCH = BAC, then SinBCH = 5/7.
SinBCH = BH / BC.
BH = BC * SinBCH = 35 * 5/7 = 25 cm.
Answer: The length of the segment BH is 25 cm.
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