In triangle ABC, angle C is 90, CH is height, angle A is 30, AB = 2. Find AH.

Since the angle C is 90 °, the triangle ABC is right-angled, its leg AC will be equal to:

AC = AB * cos (A) = 2 * cos (30 °) = 2 * √3 / 2 = √3.

Since CH is height, triangle CHA is also right-angled, then:

AH = AC * cos (A) = √3 * cos (30 °) = √3 * √3 / 2 = 3/2.

Answer: the desired value of AH is 3/2.



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