In triangle ABC, angle C is 90, CH is height, angle A is 30, AB is 22. Find AH.

1) the leg, lying opposite an angle of 30 degrees, is equal to half of the hypotenuse. CB = 11
2) by the Pythagorean theorem, AC = 3√7.
3) let x-an, then 22-x-HB
4) grow CH ^ 2 from different triangs asn and snv and equate:
63-x ^ 2 = 121-22-x
-x ^ 2 + x-36 = 0
D = 1 + 144 = 145
X = (-1 + √145) / 2



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