In triangle ABC, angle C is 90 cosA = √3 / 2, BC = 1 find AB.

univerkov | September 10, 2021 | education

Determine the sine of the angle BAC.

Sin2BAC = 1 – Cos2BAC = 1 – 3/4 = 1/4.

SinBAC = 1/2.

Then SinBAC = BC / AB.

AB = BC / SinBAC = 1 / (1/2) = 2 cm.

Answer: The length of the hypotenuse AB is 2 cm.

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