In triangle ABC, angle C is 90, cosA = 0.24, find sinB.

Find the sin B of the triangle abc if the angle c is 90, cos A = 0.24.

We apply the formulas.

sin b = (opposite leg AC) / (hypotenuse AB);

cos a = (adjacent leg AC) / (hypotenuse AB);

Since cos a = sin b, then sin b = cos a = 0.24.

Answer: sin b = 0.24.



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