In triangle ABC, angle C is 90 degrees AB = 16 AC =?
| June 16, 2021 | education
Given:
Triangle ABC;
angle C = 90 degrees;
AB = 20;
AC = 16;
Find sin a.
Decision:
BC = √ (AB ^ 2 – AC ^ 2) = √ (20 ^ 2 – 16 ^ 2) = √ (400 – 256) = √144 = 12;
sin a = BC / AB = 12/20;
Reduce the numerator and denominator in the fraction on the right side of the expression by 4, then we get:
sin a = 3/5 = 0.6.
Answer: sin a = 0.6.
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