In triangle ABC, angle C is 90 degrees AB = 16 cosa = √15 / 4. Find aircraft.

Determine the sine of the angle BAC.

Cos2BAC + Sin2BAC = 1.

Sin2BAC = 1 – Cos2BAC = 1 – 15/16 = 1/16.

SinBAC = 1/4.

Determine the length of the BC leg.

SinBAC = BC / AB.

BC = AB * SinBAC = 16 * 1/4 = 4 cm.

Answer: The length of the BC leg is 4 cm.



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