In triangle ABC, angle C is 90 degrees, AB = 5, cosA = 0.8. Find BC.

Since the angle is C = 90 °, the triangle ABC is right-angled, then, by the definition of the cosine of the angle, we obtain the equality:

AC = AB * cos (A) = 5 * 0.8 = 4.

Using the Pythagorean theorem, we find the leg BC:

BC = √ (AB) ^ 2 – (AC) ^ 2 = √ (5 ^ 2 – 4 ^ 2 = 3.

Answer: the required leg is equal.



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