In triangle ABC, angle C is 90 degrees, AB = 5, cosB = 3/5 Find AC

1) By the definition of the cosine of the angle, we get that BC / AB = 3/5, whence BC = AB * (3/5) = 5 * (3/5) = 3.
2) Now, to find AC, we use the Pythagorean theorem: AC ^ 2 + BC ^ 2 = AB ^ 2, whence AC = √ (AB ^ 2 – BC ^ 2) = √ (5 ^ 2 – 3 ^ 2) = √ (25 – 9) = √ (16) = 4.
ANSWER: AC = 4.



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