In triangle ABC, angle C is 90 degrees AB = 5, sin A = 3/5, find AC.
| December 18, 2020 | education
sin = opposite leg / hypotenuse sinA = CB / AB 3/5 = CB / 5, => CB = 3 By the Pythagorean theorem: CB ^ 2 + AC ^ 2 = AB ^ 2, AC = √ (25-9) = 4
Answer: 4
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