In triangle ABC, angle C is 90 degrees. AC = 15, AB = 5√10. Find tgB

Decision:
1) tg A = BC \ AC (by definition)
2) tg B = AC \ BC = ctg A (by definition)
3) BC = √AB ^ 2 – AC ^ 2
4) BC = √ 5 √10 ^ 2 – 15 ^ 2 = √250 – 225 = √of 25 = 5 cm.
5) tg B = 15 \ 5 = 3
Answer: tg B = 3



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