In triangle ABC, angle C is 90 degrees AC = 15, BC = 5 √91. Find: sin B.
| March 25, 2021 | education
we find the hypotenuse AB in the right-angled triangle ABC according to the Pythagorean theorem: AB = sqrt (AC ^ 2 + BC ^ 2) = sqrt (225 + 25 * 91) = sqrt (2500) = 50. sin B in a right-angled triangle is equal to the ratio of the opposite AC leg to the hypotenuse AB. sin B = AC \ AB = 15 \ 50 (reduce the fraction by) = 3 \ 10 = 0.3
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