In triangle ABC, angle C is 90 degrees AC = 16 tg A = 0.25. Find the aircraft.

Find the BC leg if it is known that:

Rectangular triangle with angle С = 90 °;
AC = 16;
tg A = 0.25.
Decision:

If you know the tangent of angle A and the leg adjacent to it, then we can find the leg opposite to it, that is, the BC side.

We get the formula:

tg A = BC / AC;

From here we will express BC.

BC = AC * tg A;

Substitute the known values of the leg and tangent of the angle, find the second leg. We get:

BC = 16 * 0.25 = 16 * 25/100 = 16 * 1/4 = 16/4 = 4;

This means that the second leg BC of triangle ABC is 4.

Answer: BC = 4.