In triangle ABC, angle C is 90 degrees, AC = 4, cos A = 0.8 Find AB.

Given:

ABC is a right-angled triangle.

cos A = 0.8.

AC = 4.

Angle C = 90 °.

Decision:

cos angle = adjacent leg / hypotenuse.

cos A = AC / AB = 0.8; now we substitute their numerical value instead of the sides.

4 / AB = 0.8; the same equation can be represented as 4 / AB = 0.8 / 1; we multiply the cross by the cross.

AB = 4 / 0.8.

AB = 5. (hypotenuse)

This is an Egyptian triangle with sides: 3: 4: 5.



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