In triangle ABC, angle C is 90 degrees BC = 15, AB = 17 find tgA

By condition, a right-angled triangle ABC is specified (angle C is 90 degrees).

It is known that the tangent is a function of the angle, equal in a right-angled triangle to the ratio of the leg, which lies opposite the given acute angle, to the other leg.

In this case, it can be expressed as

tg A = BC / AC.

The unknown leg AC, adjacent to the corner A, is determined by the Pythagorean theorem:

AC ^ 2 = AB ^ 2 – BC ^ 2, where

where AB is the hypotenuse of triangle ABC, and BC is the leg opposite to angle A.

AC ^ 2 = 17 ^ 2 – 15 ^ 2 = 64 = 8 ^ 2.

tg A = 15/8.