In triangle ABC, angle C is 90 degrees, BC = 2, sinA = 0.4. Find AB

Since the angle BCA = 90 in the ABC triangle, the ABC triangle is rectangular.

In a right-angled triangle, the sine of an acute angle is the ratio of the length of the opposite leg to the length of the hypotenuse.

SinBAC = BC / AB.

AB = BC / SinBAC = 2 / 0.4 = 5 cm.

Answer: The length of the hypotenuse AB is 5 cm.



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