In triangle ABC, angle C is 90 degrees, BC = 9, sin A = 0.6 Find AB
| August 10, 2021 | education
Consider triangle ABC, angle ACB = 90 degrees, so it is straight, therefore triangle ABC is rectangular.
angle ACB = sin alpha = 0.6
In a right-angled triangle, sine alpha is equal to the ratio of the opposite leg to the hypotenuse:
sin alpha = BC / AB
AB = BC / sin alpha
AB = 9 / 0.6
AB = 15
Answer: 15
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