In triangle ABC, angle C is 90 degrees. CH-height, BC = 14, sin A = 0.7. Find BH.
| January 9, 2021 | education
In a right-angled triangle, the sine of one acute angle is equal to the cosine of another acute angle.
SinBAC = CosABC = 0.7.
Since CH is the height of the ABC triangle, then the СНВ triangle is rectangular, with the BC leg = 14 cm, then CosHBC = ВН / BC.
0.7 = ВН / 14.
BH = 14 * 0.7 = 9.8 cm.
Answer: The length of the ВН segment is 9.8 cm.
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