In triangle ABC, angle C is 90 degrees, CH is height, AC = 10, AH = 8. Find cos B?

univerkov | August 3, 2021 | education

Since CH is the height, then the ACН triangle is rectangular, then CosA = AH / AC = 8/10 = 0.8.

The sine of one acute angle of a right triangle is equal to the cosine of another acute angle.

SinB = CosA = 0.8.

Cos2B = 1 – Sin2B = 1 – 0.64 = 0.36.

CosB = 0.6.

Answer: CosB = 0.6.

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