In triangle ABC, angle C is 90 degrees, CH is height, angle A is 30 degrees, AB = 80. Find BH.

In a right-angled triangle ABC:
СB = 1 / 2АВ = 1/2 * 80 = 40cm.
Consider a triangle BHC, write down the sine of an angle C 30 °:
sin C = HB / CB, hence:
HB = sin 30 ° * CB = 1/2 * 40 = 20 cm.
Answer: HB = 20 cm.



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