In triangle ABC, angle C is 90 degrees, CH is height, BC = 10, BH = 6. Find cos A?
| August 3, 2021 | education
Since CH is the height, then the triangle BCH is rectangular, then CosB = BH / BC = 8/10 = 0.8.
The sine of one acute angle of a right triangle is equal to the cosine of another acute angle.
SinA = CosB = 0.8.
Cos2A = 1 – Sin2A = 1 – 0.64 = 0.36.
CosA = 0.6.
Answer: CosA = 0.6.
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