In triangle ABC, angle C is 90 degrees, cos A = 0.48 Find sin B?
| May 11, 2021 | education
Given:
ABC – right triangle;
Angle C = 90 degrees;
cos A = 0.48;
Find sin B.
Decision:
cos a = AC / AB;
sin b = AC / AB;
Hence it is seen that cos a = AC / AB = sin b;
Since cos a is known and is equal to cos a = 0.48, then sin b = cos a = 0.48.
Answer: sin b = 0.48.
Answer: AB = 6.25.
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