In triangle ABC, angle C is 90 degrees, cos A = 0.8. Find tg A?

univerkov | August 3, 2021 | education

Determine the sine of the angle BAC.

Sin2BAC = 1 – Cos2BAC = 1 – 0.64 = 0.36.

SinBAC = 0.6.

Then tgBAC = SinBAC / CosBAC = 0.6 / 0.8 = 0.75.

Answer: tgBAC = 0.75.

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