In triangle ABC, angle C is 90 degrees, cos B = 0.5, AB = 16. Find BC.

univerkov | June 17, 2021 | education

Since CosABC = 0.5 = 1/2, the angle ABC = arcos (1/2) = 60.

Then the angle BAC = (90 – 60) = 30, against which the leg BC is located, the length of which is then equal to half AB.

BC = AB / 2 = 16/2 = 8 cm.

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