In triangle ABC, angle C is 90 degrees, cosA = 0.48. Find sinB.
| September 4, 2021 | education
In triangle ABC:
Angle C = 90 °;
cos A = 0.48.
Find sin B.
sin b = AC / AB (ratio of the opposite leg to the hypotenuse);
cos a = AC / AB (ratio of the adjacent leg to the hypotenuse);
Hence we see that cos a = sin b.
Hence, sin b = cos a = 0.48.
Answer: sin b = 0.48.
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