In triangle ABC, angle C is 90 degrees. cosA = 3/10. find sinB

Consider a triangle with a leg 3 and a hypotenuse 10. Since the angle C is a straight line (a rectangular triangle), we find the second leg by the Pythagorean theorem:

√ (10 ^ 2 – 3 ^ 2) = √91.

Then, by determining the sine of the angle, we get:

sin (B) = √91 / 10.

Answer: the sought sine of angle B is √91 / 10.



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