In triangle ABC, angle C is 90 degrees. cosB = 1/10. Find sinA
| April 3, 2021 | education
Since the angle is C = 90, the triangle ABC is rectangular.
By the property of acute angles of a right-angled triangle: the sine of one acute angle is equal to the cosine of the second acute angle.
(A + B) = 90.
A = 90 – B.
SinA = Sin (90 – B) = CosB.
Then SinA = CosB = 1/10.
Answer: The sine of angle A is 1/10.
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