In triangle ABC, angle C is 90 degrees sin A = 0.6. Find cos B

Since SinA = 0.6, then let BC = 6 * X cm, AB = 10 * X cm.

The cosine of an acute angle of a right-angled triangle is the ratio of the length of the adjacent leg to the length of the hypotenuse.

CosB = BC / AB = 6 * X / 10 * X = 0.6.

Answer: The cosine of angle B is 0.6.



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