In triangle ABC, angle C is 90 degrees sin B = 0.4. Find the sine of the outer angle at vertex B

To solve this task, you need to find the outer angle at the vertex B of a right-angled triangle. Let’s consider the condition and analyze it.

According to the condition of the task, we are given a right-angled triangle, in which the angle C is straight and, accordingly, is equal to ninety degrees, it is also known that the sine of the angle B is equal to 0.4.

Since the triangle is rectangular, the two remaining corners are sharp and, accordingly, the outer angle at the vertex B will be obtuse.

Since the sine of angle B is equal to 0.4 sinB = 0.4, hence the sine of the outer angle will be;

sinBin = (P – 0.4).