In triangle ABC, angle C is 90 degrees, Sin B = 5 \ √41, which is Tg A

Since C = 90 °, the triangle is right-angled, we denote its hypotenuse by c, then the leg will be equal to:

c * sin (B) = c * 5 / √41.

Find the second leg according to the Pythagorean theorem:

√ (c ^ 2 – c ^ 2 (5 / √41) ^ 2 = c * √ (1 – 25/41) = c * 4 / √41.

The tangent A will be equal to the ratio of the legs:

tg (A) = c * 5 / √41: c * 4 / √41 = 5/4.