In triangle ABC, angle C is 90 degrees sinA = 0.1 AC = 3√11. find AB.
| September 6, 2021 | education
In a right-angled triangle ABC, we define the cosine of the angle BAC.
Sin2BAC + Cos2BAC = 1.
Cos2BAC = 1 – Sin2BAC = 1 – 1/100 = 99/100.
CosBAC = √99 / 10.
Then: CosBAC = AC / AB.
AB = AC / CosBAC = 3 * √11 / (√99 / 10) = 10 * 3 * √11 / √99 = 10 cm.
Answer: The length of the hypotenuse AB is 10 cm.
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