In triangle ABC, angle C is 90 degrees, the sine of angle A is 12/13. What is the AC leg if the hypotenuse is 13 cm.

From the basic trigonometric identity, we determine the cosine of the angle BAC.

Sin2BAC + Cos2BAC = 1.

Cos2BAC = 1 – Sin2BAC = 1 – 144/169 = 25/169.

CosBAC = 5/13.

In a right-angled triangle, the cosine of its acute angle is the ratio of the length of the adjacent leg to the length of the hypotenuse.

CosBAC = AC / AB.

AC = AB * CosBAC = 13 * 5/13 = 5 cm.

Answer: The length of the AC leg is 5 cm.



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