In triangle ABC, angle C is 90 °, sin A = 3/5 AB = 10 find AC.

Let’s take into account that the sine of the angle is the ratio of the opposite leg to the hypotenuse. So, we can write down the aspect ratio: 3/5 = CB / AB.

Let’s use the “crosswise” method: 5 * CB = 3 * AB.

We find CB: CB = AB * 3/5 = 10 * 3/5 = 2 * 3 = 6.

Now, using the Pythagorean theorem, we will find the side of AC: AC^2 = AB^2 – BC^2 = 10 * 10 – 6 * 6 = 100 – 36 = 64. So AC = 8.

Answer: 8.