In triangle ABC, angle C is 90g BC = 8 sinA = 0.4 Find AB
| May 18, 2021 | education
The sine of an acute angle of a right-angled triangle is the ratio of the leg opposite to this angle to the hypotenuse. In triangle ABC, the opposite leg to angle A is leg BC. Hypotenuse – AB side (lies opposite the right angle)
sin A = BC / AB;
AB = BC / sin A;
AB = 8 / 0.4 = 20.
Answer. twenty.
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