In triangle ABC, angle c is equal to 15 degrees AK bisector of angle A, angle AKB is 70 degrees. Find angle B.

In the ABC triangle it is known:
Angle C = 15 °;
AK = bisector of angle A;
Angle AKВ = 70 °.
Find corner B.
Decision:
1) Consider the triangle AKС.
Since the angle AKВ = 70 °, then the angle СKA = 180 ° – 70 ° = 130 °.
2) In triangle AKС 2 angles are known, then we will find the third angle KAС.
КАС angle = 180 ° – 130 ° – 15 ° = 50 ° – 15 ° = 35 °.
3) Since the bisector divides the angle in half, so we find the angle A.
Angle A = 2 * 35 ° = 70 °.
4) Consider triangle ABC.
2 angles are known in it, then we find the third angle B.
Angle B = 180 ° – 70 ° – 15 ° = 110 ° – 15 ° = 95 °.
Answer: angle B = 95 °.