In triangle ABC, angle C is straight, angle A is 70 degrees. CD bisector. Find the angles of the triangle ВСD.

The ABC triangle is rectangular, then the angle ABC = (180 – ACB – BAC) = (180 – 90 – 70) = 20.

Since CD is the bisector of the angle ACB, and the angle ACB = 90, then the angle BCD = 90/2 = 45.

Then in the triangle ВСD the angle ВDC = (180 – CBD – ВСD) = (180 – 20 – 45) = 115.

Answer: The angles of the triangle ВСD are equal to 20, 45, 115.



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